Locate the image formed by refraction in the | vedclass

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(A) Given: $\mu_{1} = 1.0$,$\mu_{2} = 1.5$,$R = +20 \, cm$ (as the center of curvature $C$ is to the right of the pole $P$),and $u = -25 \, cm$ (as th

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$100 \, cm$ to the left

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(A) Given: $\mu_{1} = 1.0$,$\mu_{2} = 1.5$,$R = +20 \, cm$ (as the center of curvature $C$ is to the right of the pole $P$),and $u = -25 \, cm$ (as the object $S$ is to the left of the pole $P$).Using the refraction formula at a spherical surface:$\frac{\mu_{2}}{v} - \frac{\mu_{1}}{u} = \frac{\mu_{2} - \mu_{1}}{R}$Substituting the values:$\frac{1.5}{v} - \frac{1.0}{-25} = \frac{1.5 - 1.0}{20}$$\frac{1.5}{v} + \frac{1}{25} = \frac{0.5}{20}$$\frac{1.5}{v} = \frac{1}{40} - \frac{1}{25}$$\frac{1.5}{v} = \frac{5 - 8}{200} = \frac{-3}{200}$$v = \frac{1.5 	imes 200}{-3} = -100 \, cm$The negative sign indicates that the image is formed $100 \, cm$ to the left of the pole $P$.

Locate the image formed by refraction in the situation shown in the figure.

Similar Questions

Explain the refraction by two transparent spherically curved surfaces.

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